Aarya - Maths tutor - Chennai
Aarya - Maths tutor - Chennai

The profile of Aarya and their contact details have been verified by our experts

Aarya

  • Rate PKR 880
  • Response 1h
  • Students

    Number of students Aarya has accompanied since arriving at Superprof

    1

    Number of students Aarya has accompanied since arriving at Superprof

Aarya - Maths tutor - Chennai
  • 5 (3 reviews)

PKR 880/hr

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  • Maths
  • Algebra
  • Trigonometry
  • Arithmetic
  • Geometry

2nd year engineering student pursuing ECE from Vellore Institute of Technology, proficient in mental maths and problem solving

  • Maths
  • Algebra
  • Trigonometry
  • Arithmetic
  • Geometry

Lesson location

Recommended

Aarya is a respected member of our tutor community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.

About Aarya

As a kid, I found math to be just another subject filled with boring books and endless memorization. It never felt exciting—until I started turning it into games. Instead of just solving problems, I played with numbers, turning equations into puzzles and challenges. Now, as an engineering student, I use the same approach to teach my roommates, friends, and even my younger cousins. Watching them go from fearing math to enjoying it, sharpening their skills along the way, has been incredibly rewarding. Math is no longer a ghost to them—it’s just another puzzle waiting to be solved.

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About the lesson

  • Primary
  • Middle School
  • SSC
  • +2
  • levels :

    Primary

    Middle School

    SSC

    HSSC

    Pre-Primary

  • English

All languages in which the lesson is available :

English

Aren't you bored of studying trigonometry in the same old way what if you are an explorer searching for an ancient relic hidden deep in a lost temple. The only way to navigate through obstacles and find the relic is by using trigonometry!

Challenge 1: The Rope Bridge (Right Triangle Basics)

You reach a broken rope bridge across a canyon. A tree stands 20m away, and a vine is tied 30m up in the tree. You need to calculate the angle at which you must swing to reach the other side safely.

Problem:
Find θ, where:

Opposite = 30m (height of the tree)

Adjacent = 20m (distance to the tree)

tan(θ) = opposite/adjacent


Solution:
θ = tan⁻¹(30/20) = tan⁻¹(1.5) ≈ 56.3°

Simple enough isn't it well it can be even more fun and insightful with me not only for trigonometry but for anything that you can think of at this point in mathematics you name it and you learn it easily with me.

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Rates

Rate

  • PKR 880

Pack prices

  • 5h: PKR 4,252
  • 10h: PKR 7,331

online

  • PKR 880/h

Details

Will include personally dedicated 1 hour to the student, the fees includes extra doubt sessions and tests and quizzes as well

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